Geometrie-Dreieck-Rechtwinkliges Dreieck

$A = \frac{a\cdot b}{ 2}$
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$a = \frac{A \cdot 2}{ b}$
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$b = \frac{A \cdot 2}{ a}$
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$a^{2} + b^{2}=c^{2}$
$c =\sqrt{a^{2} + b^{2} }$
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$a =\sqrt{c^{2} - b^{2} }$
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$b =\sqrt{c^{2} - a^{2} }$
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$h^{2} = p\cdot q$
$h = \sqrt{p\cdot q}$
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$q = \frac{h^{2} }{p}$
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$p = \frac{h^{2} }{q}$
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$a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
$a = \sqrt{c\cdot p}$
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$c = \frac{a^{2} }{p}$
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$p = \frac{a^{2} }{c}$
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Beispiel Nr: 03
$\begin{array}{l} \text{Gegeben:}\\\text{Kathete} \qquad b \qquad [m] \\ \text{Fläche des Dreiecks} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Gegenkathete zu} \alpha \qquad a \qquad [m] \\ \\ a = \frac{A \cdot 2}{ b}\\ \textbf{Gegeben:} \\ b=\frac{1}{2}m \qquad A=4m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ a = \frac{A \cdot 2}{ b} \\ b=\frac{1}{2}m\\ A=4m^{2}\\ a = \frac{4m^{2} \cdot 2}{ \frac{1}{2}m}\\\\a=16m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline \frac{1}{2} m \\ \hline 5 dm \\ \hline 50 cm \\ \hline 500 mm \\ \hline 5\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 4 m^2 \\ \hline 400 dm^2 \\ \hline 4\cdot 10^{4} cm^2 \\ \hline 4\cdot 10^{6} mm^2 \\ \hline \frac{1}{25} a \\ \hline 0,0004 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 16 m \\ \hline 160 dm \\ \hline 1,6\cdot 10^{3} cm \\ \hline 1,6\cdot 10^{4} mm \\ \hline 1,6\cdot 10^{7} \mu m \\ \hline \end{array} \end{array}$