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$ A = \frac{a\cdot b}{ 2} $
$ a = \frac{A \cdot 2}{ b} $
$ b = \frac{A \cdot 2}{ a} $
$ c =\sqrt{a^{2} + b^{2} } $
$ a =\sqrt{c^{2} - b^{2} } $
$ b =\sqrt{c^{2} - a^{2} } $
$ h = \sqrt{p\cdot q} $
$ q = \frac{h^{2} }{p} $
$ p = \frac{h^{2} }{q} $
$ a = \sqrt{c\cdot p} $
$ c = \frac{a^{2} }{p} $
$ p = \frac{a^{2} }{c} $
Geometrie-Dreieck-Rechtwinkliges Dreieck
$A = \frac{a\cdot b}{ 2}$
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$a = \frac{A \cdot 2}{ b}$
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$b = \frac{A \cdot 2}{ a}$
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$a^{2} + b^{2}=c^{2}$
$c =\sqrt{a^{2} + b^{2} }$
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$a =\sqrt{c^{2} - b^{2} }$
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$b =\sqrt{c^{2} - a^{2} }$
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$h^{2} = p\cdot q$
$h = \sqrt{p\cdot q}$
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$q = \frac{h^{2} }{p}$
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$p = \frac{h^{2} }{q}$
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$a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
$a = \sqrt{c\cdot p}$
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$c = \frac{a^{2} }{p}$
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$p = \frac{a^{2} }{c}$
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Beispiel Nr: 02
$\begin{array}{l}
\text{Gegeben:}\\\text{Hypotenusenabschnitt} \qquad p \qquad [m] \\
\text{Höhe} \qquad h \qquad [m] \\
\\ \text{Gesucht:} \\\text{Hypotenusenabschnitt} \qquad q \qquad [m] \\
\\ q = \frac{h^{2} }{p}\\ \textbf{Gegeben:} \\ p=5m \qquad h=8m \qquad \\ \\ \textbf{Rechnung:} \\
q = \frac{h^{2} }{p} \\
p=5m\\
h=8m\\
q = \frac{(8m)^{2} }{5m}\\\\q=12\frac{4}{5}m
\\\\\\ \small \begin{array}{|l|} \hline p=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 8 m \\ \hline 80 dm \\ \hline 800 cm \\ \hline 8\cdot 10^{3} mm \\ \hline 8\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline q=\\ \hline 12\frac{4}{5} m \\ \hline 128 dm \\ \hline 1,28\cdot 10^{3} cm \\ \hline 1,28\cdot 10^{4} mm \\ \hline 1,28\cdot 10^{7} \mu m \\ \hline \end{array} \end{array}$