Geometrie-Dreieck-Rechtwinkliges Dreieck

$A = \frac{a\cdot b}{ 2}$
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$a = \frac{A \cdot 2}{ b}$
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$b = \frac{A \cdot 2}{ a}$
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$a^{2} + b^{2}=c^{2}$
$c =\sqrt{a^{2} + b^{2} }$
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$a =\sqrt{c^{2} - b^{2} }$
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$b =\sqrt{c^{2} - a^{2} }$
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$h^{2} = p\cdot q$
$h = \sqrt{p\cdot q}$
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$q = \frac{h^{2} }{p}$
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$p = \frac{h^{2} }{q}$
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$a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
$a = \sqrt{c\cdot p}$
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$c = \frac{a^{2} }{p}$
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$p = \frac{a^{2} }{c}$
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Beispiel Nr: 09
$\begin{array}{l} \text{Gegeben:}\\ \text{Kathete} \qquad a \qquad [m] \\ \text{Kathete} \qquad b \qquad [m] \\ \\ \text{Gesucht:} \\\text{Hypotenuse} \qquad c \qquad [m] \\ \\ c =\sqrt{a^{2} + b^{2} }\\ \textbf{Gegeben:} \\ a=1\frac{2}{3}m \qquad b=\frac{4}{5}m \qquad \\ \\ \textbf{Rechnung:} \\ c =\sqrt{a^{2} + b^{2} } \\ a=1\frac{2}{3}m\\ b=\frac{4}{5}m\\ c =\sqrt{(1\frac{2}{3}m)^{2} + (\frac{4}{5}m)^{2} }\\\\c=1,85m \\\\\\ \small \begin{array}{|l|} \hline a=\\ \hline 1\frac{2}{3} m \\ \hline 16\frac{2}{3} dm \\ \hline 166\frac{2}{3} cm \\ \hline 1666\frac{2}{3} mm \\ \hline 1666666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline b=\\ \hline \frac{4}{5} m \\ \hline 8 dm \\ \hline 80 cm \\ \hline 800 mm \\ \hline 8\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline c=\\ \hline 1,85 m \\ \hline 18,5 dm \\ \hline 185 cm \\ \hline 1,85\cdot 10^{3} mm \\ \hline 1,85\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$