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$ A = \frac{a\cdot b}{ 2} $
$ a = \frac{A \cdot 2}{ b} $
$ b = \frac{A \cdot 2}{ a} $
$ c =\sqrt{a^{2} + b^{2} } $
$ a =\sqrt{c^{2} - b^{2} } $
$ b =\sqrt{c^{2} - a^{2} } $
$ h = \sqrt{p\cdot q} $
$ q = \frac{h^{2} }{p} $
$ p = \frac{h^{2} }{q} $
$ a = \sqrt{c\cdot p} $
$ c = \frac{a^{2} }{p} $
$ p = \frac{a^{2} }{c} $
Geometrie-Dreieck-Rechtwinkliges Dreieck
$A = \frac{a\cdot b}{ 2}$
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$a = \frac{A \cdot 2}{ b}$
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$b = \frac{A \cdot 2}{ a}$
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$a^{2} + b^{2}=c^{2}$
$c =\sqrt{a^{2} + b^{2} }$
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$a =\sqrt{c^{2} - b^{2} }$
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$b =\sqrt{c^{2} - a^{2} }$
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$h^{2} = p\cdot q$
$h = \sqrt{p\cdot q}$
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$q = \frac{h^{2} }{p}$
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$p = \frac{h^{2} }{q}$
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$a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
$a = \sqrt{c\cdot p}$
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$c = \frac{a^{2} }{p}$
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$p = \frac{a^{2} }{c}$
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Beispiel Nr: 01
$\begin{array}{l}
\text{Gegeben:}\\\text{Hypotenusenabschnitt} \qquad q \qquad [m] \\
\text{Hypotenusenabschnitt} \qquad p \qquad [m] \\
\\ \text{Gesucht:} \\\text{Höhe} \qquad h \qquad [m] \\
\\ h = \sqrt{p\cdot q}\\ \textbf{Gegeben:} \\ q=1 \qquad p=6 \qquad \\ \\ \textbf{Rechnung:} \\
h = \sqrt{p\cdot q} \\
q=1\\
p=6\\
h = \sqrt{6\cdot 1}\\\\h=2,45
\end{array}$