Geometrie-Dreieck-Rechtwinkliges Dreieck


  • $A = \frac{a\cdot b}{ 2}$
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    $a = \frac{A \cdot 2}{ b}$
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    $b = \frac{A \cdot 2}{ a}$
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    $a^{2} + b^{2}=c^{2}$
    $c =\sqrt{a^{2} + b^{2} }$
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    $a =\sqrt{c^{2} - b^{2} }$
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    $b =\sqrt{c^{2} - a^{2} }$
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    $h^{2} = p\cdot q$
    $h = \sqrt{p\cdot q}$
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    $q = \frac{h^{2} }{p}$
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    $p = \frac{h^{2} }{q}$
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    $a^{2} = c\cdot p \qquad b^{2} = c\cdot q $
    $a = \sqrt{c\cdot p}$
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    $c = \frac{a^{2} }{p}$
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    $p = \frac{a^{2} }{c}$
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Beispiel Nr: 08
$ \text{Gegeben:}\\\text{Kathete} \qquad b \qquad [m] \\ \text{Fläche des Dreiecks} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Gegenkathete zu} \alpha \qquad a \qquad [m] \\ \\ a = \frac{A \cdot 2}{ b}\\ \textbf{Gegeben:} \\ b=0,002m \qquad A=\frac{2}{5}m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ a = \frac{A \cdot 2}{ b} \\ b=0,002m\\ A=\frac{2}{5}m^{2}\\ a = \frac{\frac{2}{5}m^{2} \cdot 2}{ 0,002m}\\\\a=400m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 0,002 m \\ \hline \frac{1}{50} dm \\ \hline \frac{1}{5} cm \\ \hline 2 mm \\ \hline 2\cdot 10^{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline \frac{2}{5} m^2 \\ \hline 40 dm^2 \\ \hline 4\cdot 10^{3} cm^2 \\ \hline 4\cdot 10^{5} mm^2 \\ \hline 0,004 a \\ \hline 4\cdot 10^{-5} ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 400 m \\ \hline 4\cdot 10^{3} dm \\ \hline 4\cdot 10^{4} cm \\ \hline 4\cdot 10^{5} mm \\ \hline 4\cdot 10^{8} \mu m \\ \hline \end{array}$