$\text{Terme - Additon - Subtraktion - Mulitiplikation - Division}\\ \displaystyle \frac{ 8x^6+26}{ 2x^2-3} \ \small \begin{matrix} ( 8x^6&&&&&&+26&):( 2x^2 -3 )= 4x^4 +6x^2 +9 \\ \,-( 8x^6&&-12x^4) \\ \hline & 12x^4&&&&+26&\\ &&-( 12x^4&&-18x^2) \\ \hline &&& 18x^2&&+26&\\ &&&&-( 18x^2&&-27) \\ \hline &&&&& 53&\\ \end{matrix} \\ \normalsize \\ \\ \displaystyle \frac{ 8x^6+26}{ 2x^2-3}= 4x^4+6x^2+9+\frac{ 53}{ 2x^2-3}$