Geometrie-Viereck-Rechteck

$A = a\cdot b$
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$a = \frac{A}{b}$
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$b = \frac{A}{a}$
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$U = 2\cdot a + 2\cdot b$
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$a = \frac{U - 2\cdot b}{ 2}$
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$b = \frac{U - 2\cdot a}{ 2}$
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$d = \sqrt{a^{2} +b^{2} }$
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$b = \sqrt{d^{2} -a^{2} }$
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$a = \sqrt{d^{2} -b^{2} }$
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Beispiel Nr: 03
$\begin{array}{l} \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Länge} \qquad a \qquad [m] \\ \\ a = \frac{A}{b}\\ \textbf{Gegeben:} \\ b=3m \qquad A=4m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ a = \frac{A}{b} \\ b=3m\\ A=4m^{2}\\ a = \frac{4m^{2}}{3m}\\\\a=1\frac{1}{3}m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 3 m \\ \hline 30 dm \\ \hline 300 cm \\ \hline 3\cdot 10^{3} mm \\ \hline 3\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 4 m^2 \\ \hline 400 dm^2 \\ \hline 4\cdot 10^{4} cm^2 \\ \hline 4\cdot 10^{6} mm^2 \\ \hline \frac{1}{25} a \\ \hline 0,0004 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 1\frac{1}{3} m \\ \hline 13\frac{1}{3} dm \\ \hline 133\frac{1}{3} cm \\ \hline 1333\frac{1}{3} mm \\ \hline 1333333\frac{1}{3} \mu m \\ \hline \end{array} \end{array}$