Geometrie-Viereck-Rechteck



Beispiel Nr: 12
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Umfang} \qquad U \qquad [m] \\ \\ U = 2\cdot a + 2\cdot b\\ \textbf{Gegeben:} \\ b=\frac{2}{3}m \qquad a=2\frac{5}{7}m \qquad \\ \\ \textbf{Rechnung:} \\ U = 2\cdot a + 2\cdot b \\ b=\frac{2}{3}m\\ a=2\frac{5}{7}m\\ U = 2\cdot 2\frac{5}{7}m + 2\cdot \frac{2}{3}m\\\\U=6\frac{16}{21}m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline \frac{2}{3} m \\ \hline 6\frac{2}{3} dm \\ \hline 66\frac{2}{3} cm \\ \hline 666\frac{2}{3} mm \\ \hline 666666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 2\frac{5}{7} m \\ \hline 27\frac{1}{7} dm \\ \hline 271\frac{3}{7} cm \\ \hline 2714\frac{2}{7} mm \\ \hline 2714285\frac{5}{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline U=\\ \hline 6\frac{16}{21} m \\ \hline 67\frac{13}{21} dm \\ \hline 676\frac{4}{21} cm \\ \hline 6761\frac{19}{21} mm \\ \hline 6761904\frac{16}{21} \mu m \\ \hline \end{array}$