Geometrie-Viereck-Rechteck



Beispiel Nr: 04
$ \text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Breite} \qquad b \qquad [m] \\ \\ b = \frac{A}{a}\\ \textbf{Gegeben:} \\ A=13m^{2} \qquad a=9m \qquad \\ \\ \textbf{Rechnung:} \\ b = \frac{A}{a} \\ A=13m^{2}\\ a=9m\\ b = \frac{13m^{2}}{9m}\\\\b=1\frac{4}{9}m \\\\\\ \small \begin{array}{|l|} \hline A=\\ \hline 13 m^2 \\ \hline 1,3\cdot 10^{3} dm^2 \\ \hline 1,3\cdot 10^{5} cm^2 \\ \hline 1,3\cdot 10^{7} mm^2 \\ \hline \frac{13}{100} a \\ \hline 0,0013 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 9 m \\ \hline 90 dm \\ \hline 900 cm \\ \hline 9\cdot 10^{3} mm \\ \hline 9\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline b=\\ \hline 1\frac{4}{9} m \\ \hline 14\frac{4}{9} dm \\ \hline 144\frac{4}{9} cm \\ \hline 1444\frac{4}{9} mm \\ \hline 1444444\frac{4}{9} \mu m \\ \hline \end{array}$