Geometrie-Viereck-Rechteck



Beispiel Nr: 09
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = a\cdot b\\ \textbf{Gegeben:} \\ b=\frac{2}{3}m \qquad a=\frac{4}{9}m \qquad \\ \\ \textbf{Rechnung:} \\ A = a\cdot b \\ b=\frac{2}{3}m\\ a=\frac{4}{9}m\\ A = \frac{4}{9}m\cdot \frac{2}{3}m\\\\A=\frac{8}{27}m^{2} \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline \frac{2}{3} m \\ \hline 6\frac{2}{3} dm \\ \hline 66\frac{2}{3} cm \\ \hline 666\frac{2}{3} mm \\ \hline 666666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline \frac{4}{9} m \\ \hline 4\frac{4}{9} dm \\ \hline 44\frac{4}{9} cm \\ \hline 444\frac{4}{9} mm \\ \hline 444444\frac{4}{9} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline \frac{8}{27} m^2 \\ \hline 29\frac{17}{27} dm^2 \\ \hline 2962\frac{26}{27} cm^2 \\ \hline 296296\frac{8}{27} mm^2 \\ \hline 0,00296 a \\ \hline 2,96\cdot 10^{-5} ha \\ \hline \end{array}$