Geometrie-Viereck-Rechteck

$A = a\cdot b$
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$a = \frac{A}{b}$
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$b = \frac{A}{a}$
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$U = 2\cdot a + 2\cdot b$
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$a = \frac{U - 2\cdot b}{ 2}$
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$b = \frac{U - 2\cdot a}{ 2}$
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$d = \sqrt{a^{2} +b^{2} }$
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$b = \sqrt{d^{2} -a^{2} }$
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$a = \sqrt{d^{2} -b^{2} }$
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Beispiel Nr: 05
$\begin{array}{l} \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\ \\ d = \sqrt{a^{2} +b^{2} }\\ \textbf{Gegeben:} \\ b=12m \qquad a=16m \qquad \\ \\ \textbf{Rechnung:} \\ d = \sqrt{a^{2} +b^{2} } \\ b=12m\\ a=16m\\ d = \sqrt{(16m)^{2} +(12m)^{2} }\\\\d=20m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 12 m \\ \hline 120 dm \\ \hline 1,2\cdot 10^{3} cm \\ \hline 1,2\cdot 10^{4} mm \\ \hline 1,2\cdot 10^{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 16 m \\ \hline 160 dm \\ \hline 1,6\cdot 10^{3} cm \\ \hline 1,6\cdot 10^{4} mm \\ \hline 1,6\cdot 10^{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 20 m \\ \hline 200 dm \\ \hline 2\cdot 10^{3} cm \\ \hline 2\cdot 10^{4} mm \\ \hline 2\cdot 10^{7} \mu m \\ \hline \end{array} \end{array}$