Geometrie-Viereck-Rechteck

$A = a\cdot b$
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$a = \frac{A}{b}$
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$b = \frac{A}{a}$
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$U = 2\cdot a + 2\cdot b$
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$a = \frac{U - 2\cdot b}{ 2}$
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$b = \frac{U - 2\cdot a}{ 2}$
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$d = \sqrt{a^{2} +b^{2} }$
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$b = \sqrt{d^{2} -a^{2} }$
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$a = \sqrt{d^{2} -b^{2} }$
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Beispiel Nr: 04
$\begin{array}{l} \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = a\cdot b\\ \textbf{Gegeben:} \\ b=13m \qquad a=9m \qquad \\ \\ \textbf{Rechnung:} \\ A = a\cdot b \\ b=13m\\ a=9m\\ A = 9m\cdot 13m\\\\A=117m^{2} \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 13 m \\ \hline 130 dm \\ \hline 1,3\cdot 10^{3} cm \\ \hline 1,3\cdot 10^{4} mm \\ \hline 1,3\cdot 10^{7} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 9 m \\ \hline 90 dm \\ \hline 900 cm \\ \hline 9\cdot 10^{3} mm \\ \hline 9\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 117 m^2 \\ \hline 1,17\cdot 10^{4} dm^2 \\ \hline 1,17\cdot 10^{6} cm^2 \\ \hline 1,17\cdot 10^{8} mm^2 \\ \hline 1\frac{17}{100} a \\ \hline 0,0117 ha \\ \hline \end{array} \end{array}$