Geometrie-Viereck-Rechteck



Beispiel Nr: 10
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Umfang} \qquad U \qquad [m] \\ \\ U = 2\cdot a + 2\cdot b\\ \textbf{Gegeben:} \\ b=1\frac{1}{6}m \qquad a=\frac{11}{17}m \qquad \\ \\ \textbf{Rechnung:} \\ U = 2\cdot a + 2\cdot b \\ b=1\frac{1}{6}m\\ a=\frac{11}{17}m\\ U = 2\cdot \frac{11}{17}m + 2\cdot 1\frac{1}{6}m\\\\U=3\frac{32}{51}m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 1\frac{1}{6} m \\ \hline 11\frac{2}{3} dm \\ \hline 116\frac{2}{3} cm \\ \hline 1166\frac{2}{3} mm \\ \hline 1166666\frac{2}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline \frac{11}{17} m \\ \hline 6\frac{8}{17} dm \\ \hline 64\frac{12}{17} cm \\ \hline 647\frac{1}{17} mm \\ \hline 647058\frac{14}{17} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline U=\\ \hline 3\frac{32}{51} m \\ \hline 36\frac{14}{51} dm \\ \hline 362\frac{38}{51} cm \\ \hline 3627\frac{23}{51} mm \\ \hline 3627450\frac{50}{51} \mu m \\ \hline \end{array}$