$
\text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\
\text{Länge} \qquad a \qquad [m] \\
\\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\
\\ d = \sqrt{a^{2} +b^{2} }\\ \textbf{Gegeben:} \\ b=\frac{1}{50}m \qquad a=\frac{2}{5}m \qquad \\ \\ \textbf{Rechnung:} \\
d = \sqrt{a^{2} +b^{2} } \\
b=\frac{1}{50}m\\
a=\frac{2}{5}m\\
d = \sqrt{(\frac{2}{5}m)^{2} +(\frac{1}{50}m)^{2} }\\\\d=0,4m
\\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline \frac{1}{50} m \\ \hline \frac{1}{5} dm \\ \hline 2 cm \\ \hline 20 mm \\ \hline 2\cdot 10^{4} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline \frac{2}{5} m \\ \hline 4 dm \\ \hline 40 cm \\ \hline 400 mm \\ \hline 4\cdot 10^{5} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 0,4 m \\ \hline 4 dm \\ \hline 40 cm \\ \hline 400 mm \\ \hline 4\cdot 10^{5} \mu m \\ \hline \end{array}$