Geometrie-Viereck-Rechteck

$A = a\cdot b$
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$a = \frac{A}{b}$
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$b = \frac{A}{a}$
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$U = 2\cdot a + 2\cdot b$
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$a = \frac{U - 2\cdot b}{ 2}$
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$b = \frac{U - 2\cdot a}{ 2}$
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$d = \sqrt{a^{2} +b^{2} }$
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$b = \sqrt{d^{2} -a^{2} }$
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$a = \sqrt{d^{2} -b^{2} }$
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Beispiel Nr: 01
$\begin{array}{l} \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \\ \text{Gesucht:} \\\text{Länge} \qquad a \qquad [m] \\ \\ a = \frac{A}{b}\\ \textbf{Gegeben:} \\ b=6m \qquad A=9m^{2} \qquad \\ \\ \textbf{Rechnung:} \\ a = \frac{A}{b} \\ b=6m\\ A=9m^{2}\\ a = \frac{9m^{2}}{6m}\\\\a=1\frac{1}{2}m \\\\\\ \small \begin{array}{|l|} \hline b=\\ \hline 6 m \\ \hline 60 dm \\ \hline 600 cm \\ \hline 6\cdot 10^{3} mm \\ \hline 6\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 9 m^2 \\ \hline 900 dm^2 \\ \hline 9\cdot 10^{4} cm^2 \\ \hline 9\cdot 10^{6} mm^2 \\ \hline \frac{9}{100} a \\ \hline 0,0009 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 1\frac{1}{2} m \\ \hline 15 dm \\ \hline 150 cm \\ \hline 1,5\cdot 10^{3} mm \\ \hline 1,5\cdot 10^{6} \mu m \\ \hline \end{array} \end{array}$