Geometrie-Viereck-Rechteck



Beispiel Nr: 11
$ \text{Gegeben:}\\\text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Breite} \qquad b \qquad [m] \\ \\ b = \frac{A}{a}\\ \textbf{Gegeben:} \\ A=2\frac{2}{3}m^{2} \qquad a=1\frac{2}{15}m \qquad \\ \\ \textbf{Rechnung:} \\ b = \frac{A}{a} \\ A=2\frac{2}{3}m^{2}\\ a=1\frac{2}{15}m\\ b = \frac{2\frac{2}{3}m^{2}}{1\frac{2}{15}m}\\\\b=2\frac{6}{17}m \\\\\\ \small \begin{array}{|l|} \hline A=\\ \hline 2\frac{2}{3} m^2 \\ \hline 266\frac{2}{3} dm^2 \\ \hline 26666\frac{2}{3} cm^2 \\ \hline 2666666\frac{2}{3} mm^2 \\ \hline \frac{2}{75} a \\ \hline 0,000267 ha \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 1\frac{2}{15} m \\ \hline 11\frac{1}{3} dm \\ \hline 113\frac{1}{3} cm \\ \hline 1133\frac{1}{3} mm \\ \hline 1133333\frac{1}{3} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline b=\\ \hline 2\frac{6}{17} m \\ \hline 23\frac{9}{17} dm \\ \hline 235\frac{5}{17} cm \\ \hline 2352\frac{16}{17} mm \\ \hline 2352941\frac{3}{17} \mu m \\ \hline \end{array}$